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PCB and Wire
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Multiplexer
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2. ON-resistance (RON)
3. RON flatness
4. Effective op amp gain including MUX RON
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12. Notes
TI Worldwide Technical Support

PCB microstrip capacitance and inductance

Inductance for microstrip

Equation 163.

L (nH) = k_{L} \cdot l \cdot \ln (\frac{5.98 \cdot h}{0.8 \cdot w + t})

Capacitance for microstrip

Equation 164.

C (pF) = \frac{k_{C} \cdot l \cdot (ε_{r} + 1.41)}{\ln (\frac{5.98 \cdot h}{0.8 \cdot w + t})}

Characteristic impedance for microstrip

Equation 165.

Z_{O} = \sqrt{\frac{L}{C}} = \frac{87 Ω}{\sqrt{(ε_{r} + 1.41)}} \cdot \ln (\frac{5.98 \cdot h}{0.8 \cdot w + t})

Where

k_L = PCB inductance per unit length.

Both the metric and imperial version of the constant are given.

k_L = 2nH/cm, or 5.071nH/in

k_C = PCB capacitance per unit length.

Both the metric and imperial version of the constant are given.

k_C = 0.264pF/cm, or 0.67056pF/in

l = length of microstrip (metric in cm, or imperial in inches)

w = width of microstrip (metric in mm, or imperial in mil)

t = thickness of copper (metric in mm, or imperial in mil)

h = separation between planes (metric in mm, or imperial in mil)

ε_r = PCB dielectric constant (ε_r ≈ 4.5 for FR-4)

For imperial: Copper thickness (mils) = 1.37 × (number of ounces)

i.e. 1oz Cu = 1.37mils

i.e. ?oz Cu = 0.684mils

Figure 66 PCB Microstrip capacitance and inductance

Example

Calculate the total inductance and capacitance if l = 2.54cm, w = 0.254mm, t = 0.0356mm, h = 0.8mm, and ε_r = 4.5 for FR-4.

Answer

Equation 166.

\begin{array}{l} L (nH) = (2 nH / cm) \cdot (2.54 cm) \cdot \ln (\frac{5.98 \cdot 0.8 mm}{0.8 \cdot 0.254 mm + 0.0356 mm}) = 15.2 nH \\ C (pF) = \frac{(0.264 pF / cm) \cdot (2.54 cm) \cdot (4.5 + 1.41)}{\ln (\frac{5.98 \cdot 0.8 mm}{0.8 \cdot 0.254 mm + 0.0356 mm})} = 1.3 pF \end{array}